For effective bindweed control, how many gallons of Kills-All 3L should be added to a 500 gallon tank to achieve the correct rate of 0.6 pounds a.i. per acre?

Prepare for the Agronomy Seaman FFA Test with flashcards and multiple choice questions. Each question comes with hints and explanations to ensure you are ready for your exam!

To determine the correct amount of Kills-All 3L needed for effective bindweed control, it's important to calculate the application rate based on the total tank capacity and the rate required per acre.

In this scenario, the target rate is 0.6 pounds of active ingredient (a.i.) per acre. Kills-All 3L contains a specific concentration of a.i. that needs to be considered in the calculations. Knowing the concentration of a.i. in Kills-All 3L allows for the appropriate dilution with water in a 500-gallon tank.

Typically, the label for the product will provide the concentration of the active ingredient, which can help to calculate how much product is needed to achieve the desired pounds of a.i. per acre. By determining how many gallons of Kills-All 3L contains 0.6 pounds of a.i. and then scaling that based on the number of acres being treated (in this case, one acre), you derive the correct volume to mix in the tank.

For example, if 5 gallons of Kills-All 3L contains exactly the amount of a.i. required to achieve 0.6 pounds per acre, then this is the correct amount to add to a

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