How many pounds of OpTill should be added to a 450-gallon tank for a rate of 1.5 oz active ingredient per acre?

Prepare for the Agronomy Seaman FFA Test with flashcards and multiple choice questions. Each question comes with hints and explanations to ensure you are ready for your exam!

To determine the correct amount of OpTill that should be added to a 450-gallon tank for a rate of 1.5 ounces of active ingredient per acre, it's important to understand how to calculate the total weight needed based on the required application rate.

First, we need to consider the conversion from ounces to pounds, since the packaging of OpTill is likely in pounds. There are 16 ounces in a pound, so 1.5 ounces is equivalent to 1.5/16 pounds, which is approximately 0.09375 pounds of active ingredient needed per acre.

Next, it's essential to know the number of acres that can be treated with a 450-gallon tank. Assuming an average application rate, a commonly used figure is that a typical liquid application is around 20 gallons per acre. Therefore, a 450-gallon tank would be able to treat approximately 22.5 acres (450 gallons divided by 20 gallons per acre).

Now, to find the total pounds of active ingredient needed for 22.5 acres, we multiply the amount of active ingredient per acre (approximately 0.09375 pounds) by 22.5 acres, which results in around 2.1 pounds of active ingredient for

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